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I require assistance. - Printable Version

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I require assistance. - Medontthink - 3-30-15 11:43 AM

An= n*sin(1/n)

Lim n->infinity sin(1/n) / 1/n

Let T= 1/n

Lim n->infinity sin(t)/t, L`--> cos(1/n) / 1 --> 1/1=1

Or am I dumb?


RE: I require assistance. - Beaverboys - 3-30-15 12:59 PM

wow such smart very impress


RE: I require assistance. - rMv - 3-30-15 8:05 PM

Wrong forum


RE: I require assistance. - Chosen - 3-30-15 8:47 PM

Make sure you take the correspondent number off and remove the infinity (sin) and replace it with T = 4/5